16. Integration
CollegeIntegration is differentiation run backwards, and simultaneously a way to add up infinitely many infinitesimal pieces. It computes areas, totals and accumulations — completing the two halves of calculus.
Antiderivatives and the definite integral
An antiderivative of f is a function F whose derivative is f. The indefinite integral collects all of them (they differ by a constant):
∫ (1/x) dx = ln|x| + C
The definite integral ∫ab f(x) dx is the signed area between the curve and the x-axis from a to b, defined as the limit of summing thin rectangles (a Riemann sum). The two ideas are joined by the crowning result of calculus:
Adding up infinitely thin slices
To find the area under a curve, chop the region into many thin vertical strips, each almost a rectangle of height f(x) and width dx. Add their areas and you approximate the total; let the strips become infinitely thin and the approximation becomes exact. That limiting sum is the integral — the elongated S of ∫ is literally an old-style "S" for "sum."
The astonishing part is the Fundamental Theorem: this messy infinite sum can be computed by finding an antiderivative and subtracting two values. It says accumulation (integration) and rate-of-change (differentiation) are two sides of one coin. Intuitively, if you know your speed at every instant (a rate), integrating it gives the total distance travelled (an accumulation) — and that is exactly F(b) − F(a).
Worked example: area under a parabola
Find the area under y = x² from x = 0 to x = 3.
- Set up the definite integral: ∫03 x² dx.
- Find an antiderivative: F(x) = x³/3 (since d/dx[x³/3] = x²).
- Apply the Fundamental Theorem: F(3) − F(0) = 27/3 − 0 = 9.
- Sanity check: the region sits inside the 3×9 bounding rectangle (area 27) and fills exactly one third — consistent with area 9. ✓
Answer: the area is 9 square units.
Test your understanding
Why is there always a "+ C" on an indefinite integral?
Because the derivative of any constant is 0, adding a constant to an antiderivative does not change its derivative. So if F(x) works, so does F(x) + 5 or F(x) − 100. The + C represents this whole family. In a definite integral the constant cancels in the subtraction, which is why it disappears there.
Evaluate ∫₁² (2x + 3) dx.
Antiderivative: x² + 3x. Evaluate: at 2, 4 + 6 = 10; at 1, 1 + 3 = 4. Difference 10 − 4 = 6. Geometrically this is the area of a trapezium under the line from x = 1 to x = 2.
What does it mean if a definite integral comes out negative?
It means the curve lies below the x-axis over that interval, so the "signed area" is negative. The integral counts area above the axis as positive and below as negative. To get the total physical area regardless of sign, integrate the absolute value, splitting the interval where the curve crosses the axis.
How are the derivative and the integral inverse to each other?
The Fundamental Theorem states it in two directions: differentiating an integral recovers the original function, d/dx ∫ₐˣ f(t) dt = f(x); and integrating a derivative recovers the original (up to endpoints), ∫ₐᵇ F′(x) dx = F(b) − F(a). One undoes the other, which is why every derivative rule has a matching integral rule.
How the ideas connect
Every key idea in this chapter, branching from the core concept — use it to see the whole picture at a glance.
The process, step by step
Worked problems, step by step
Follow each solution line by line, then try to reproduce it on paper before moving on.
Example 1Find the integral of 2x with respect to x.
- Raise the power and divide: x^2
- Add the constant of integration
- Result is x^2 + C
Example 2Find the area under y = x^2 from 0 to 3.
- Antiderivative is x^3/3
- Evaluate 3^3/3 - 0 = 27/3
- Area = 9
Now you try
Work each one out first, then tap to reveal the worked answer.